Base | Representation |
---|---|
bin | 11001101110001101110101… |
… | …111100001110010111111101 |
3 | 112211112211212122220120121121 |
4 | 121232031311330032113331 |
5 | 104311433321304044013 |
6 | 1040333514344030541 |
7 | 32554110356666101 |
oct | 3156156574162775 |
9 | 484484778816547 |
10 | 113127122331133 |
11 | 33055a41379869 |
12 | 10830964462451 |
13 | 4b17ac3753631 |
14 | 1dd154c061901 |
15 | d12a6933c58d |
hex | 66e375f0e5fd |
113127122331133 has 4 divisors (see below), whose sum is σ = 113184055962880. Its totient is φ = 113070188699388.
The previous prime is 113127122331127. The next prime is 113127122331149. The reversal of 113127122331133 is 331133221721311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 113127122331133 - 213 = 113127122322941 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113127122331233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28466812893 + ... + 28466816866.
It is an arithmetic number, because the mean of its divisors is an integer number (28296013990720).
Almost surely, 2113127122331133 is an apocalyptic number.
It is an amenable number.
113127122331133 is a deficient number, since it is larger than the sum of its proper divisors (56933631747).
113127122331133 is an equidigital number, since it uses as much as digits as its factorization.
113127122331133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56933631746.
The product of its digits is 13608, while the sum is 34.
The spelling of 113127122331133 in words is "one hundred thirteen trillion, one hundred twenty-seven billion, one hundred twenty-two million, three hundred thirty-one thousand, one hundred thirty-three".
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