Base | Representation |
---|---|
bin | 10101000100100111… |
… | …01010111101100111 |
3 | 1002012102101221220221 |
4 | 22202103222331213 |
5 | 141132112002140 |
6 | 5110324505211 |
7 | 550226626102 |
oct | 124223527547 |
9 | 32172357827 |
10 | 11313000295 |
11 | 4885991623 |
12 | 223884b207 |
13 | 10b3a2781c |
14 | 7946a9739 |
15 | 4632ba14a |
hex | 2a24eaf67 |
11313000295 has 8 divisors (see below), whose sum is σ = 13611422160. Its totient is φ = 9026519040.
The previous prime is 11313000277. The next prime is 11313000299. The reversal of 11313000295 is 59200031311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11313000295 - 29 = 11312999783 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11313000299) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2983066 + ... + 2986855.
It is an arithmetic number, because the mean of its divisors is an integer number (1701427770).
Almost surely, 211313000295 is an apocalyptic number.
11313000295 is a deficient number, since it is larger than the sum of its proper divisors (2298421865).
11313000295 is an equidigital number, since it uses as much as digits as its factorization.
11313000295 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5970305.
The product of its (nonzero) digits is 810, while the sum is 25.
The spelling of 11313000295 in words is "eleven billion, three hundred thirteen million, two hundred ninety-five", and thus it is an aban number.
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