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113130011330244 = 22328696893613361
BaseRepresentation
bin11001101110010000100010…
…001000111000011011000100
3112211120010100000001221100200
4121232100202020320123010
5104312010230400031434
61040335113145210500
732554242100041036
oct3156204210703304
9484503300057320
10113130011330244
1133057194114637
121083142ba90a30
134b1816414206c
141dd1743a11c56
15d12b87ca7199
hex66e4222386c4

113130011330244 has 36 divisors (see below), whose sum is σ = 285967936597980. Its totient is φ = 37709949980160.

The previous prime is 113130011330233. The next prime is 113130011330249. The reversal of 113130011330244 is 442033110031311.

113130011330244 is a `hidden beast` number, since 1 + 1 + 3 + 1 + 300 + 1 + 1 + 330 + 24 + 4 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 89386435713600 + 23743575616644 = 9454440^2 + 4872738^2 .

It is a tau number, because it is divible by the number of its divisors (36).

It is a super-2 number, since 2×1131300113302442 (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (113130011330249) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 29502124 + ... + 33115484.

Almost surely, 2113130011330244 is an apocalyptic number.

It is an amenable number.

113130011330244 is an abundant number, since it is smaller than the sum of its proper divisors (172837925267736).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113130011330244 is a wasteful number, since it uses less digits than its factorization.

113130011330244 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4483060 (or 4483055 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 113130011330244 its reverse (442033110031311), we get a palindrome (555163121361555).

The spelling of 113130011330244 in words is "one hundred thirteen trillion, one hundred thirty billion, eleven million, three hundred thirty thousand, two hundred forty-four".

Divisors: 1 2 3 4 6 9 12 18 36 869689 1739378 2609067 3478756 3613361 5218134 7226722 7827201 10436268 10840083 14453444 15654402 21680166 31308804 32520249 43360332 65040498 130080996 3142500314729 6285000629458 9427500944187 12570001258916 18855001888374 28282502832561 37710003776748 56565005665122 113130011330244