11313003000000 has 784 divisors, whose sum is σ = 40684564230912. Its totient is φ = 2757696000000.

The previous prime is 11313002999911. The next prime is 11313003000007. The reversal of 11313003000000 is 30031311.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a self number, because there is not a number n which added to its sum of digits gives 11313003000000.

It is not an unprimeable number, because it can be changed into a prime (11313003000007) by changing a digit.

It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 4172998645 + ... + 4173001355.

Almost surely, 2^{11313003000000} is an apocalyptic number.

11313003000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11313003000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20342282115456).

11313003000000 is an abundant number, since it is smaller than the sum of its proper divisors (29371561230912).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11313003000000 is an equidigital number, since it uses as much as digits as its factorization.

11313003000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2876 (or 2841 counting only the distinct ones).

The product of its (nonzero) digits is 27, while the sum is 12.

Adding to 11313003000000 its reverse (30031311), we get a palindrome (11313033031311).

The spelling of 11313003000000 in words is "eleven trillion, three hundred thirteen billion, three million", and thus it is an aban number.