11313003000001 has 4 divisors (see below), whose sum is σ = 11313861945904. Its totient is φ = 11312144054100.

The previous prime is 11313002999911. The next prime is 11313003000007. The reversal of 11313003000001 is 10000030031311.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11313003000001 - 2⁴³ = 2516909977793 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11313003000007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 429453195 + ... + 429479536.

It is an arithmetic number, because the mean of its divisors is an integer number (2828465486476).

Almost surely, 2^{11313003000001} is an apocalyptic number.

It is an amenable number.

11313003000001 is a deficient number, since it is larger than the sum of its proper divisors (858945903).

11313003000001 is an equidigital number, since it uses as much as digits as its factorization.

11313003000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 858945902.

The product of its (nonzero) digits is 27, while the sum is 13.

Adding to 11313003000001 its reverse (10000030031311), we get a palindrome (21313033031312).

The spelling of 11313003000001 in words is "eleven trillion, three hundred thirteen billion, three million, one", and thus it is an aban number.