1131300403 has 2 divisors, whose sum is σ = 1131300404. Its totient is φ = 1131300402.

The previous prime is 1131300371. The next prime is 1131300431. The reversal of 1131300403 is 3040031311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1131300403 - 2⁵ = 1131300371 is a prime.

It is not a weakly prime, because it can be changed into another prime (1131300433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565650201 + 565650202.

It is an arithmetic number, because the mean of its divisors is an integer number (565650202).

Almost surely, 2^1131300403 is an apocalyptic number.

1131300403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131300403 is an equidigital number, since it uses as much as digits as its factorization.

1131300403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 16.

The square root of 1131300403 is about 33634.8093944354. The cubic root of 1131300403 is about 1041.9798340857.

Adding to 1131300403 its reverse (3040031311), we get a palindrome (4171331714).

The spelling of 1131300403 in words is "one billion, one hundred thirty-one million, three hundred thousand, four hundred three".