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113130041 is a prime number
BaseRepresentation
bin1101011111000…
…11101000111001
321212212121020112
412233203220321
5212430130131
615120434105
72542406123
oct657435071
9255777215
10113130041
115894a302
1231a78935
131a58cc6b
141104c213
159dea02b
hex6be3a39

113130041 has 2 divisors, whose sum is σ = 113130042. Its totient is φ = 113130040.

The previous prime is 113130013. The next prime is 113130049. The reversal of 113130041 is 140031311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91776400 + 21353641 = 9580^2 + 4621^2 .

It is a cyclic number.

It is not a de Polignac number, because 113130041 - 26 = 113129977 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 113129998 and 113130025.

It is not a weakly prime, because it can be changed into another prime (113130049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56565020 + 56565021.

It is an arithmetic number, because the mean of its divisors is an integer number (56565021).

Almost surely, 2113130041 is an apocalyptic number.

It is an amenable number.

113130041 is a deficient number, since it is larger than the sum of its proper divisors (1).

113130041 is an equidigital number, since it uses as much as digits as its factorization.

113130041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 113130041 is about 10636.2606681108. The cubic root of 113130041 is about 483.6441972717.

Adding to 113130041 its reverse (140031311), we get a palindrome (253161352).

The spelling of 113130041 in words is "one hundred thirteen million, one hundred thirty thousand, forty-one".