Base | Representation |
---|---|
bin | 10101000100100111… |
… | …01101011010011111 |
3 | 1002012102102110200210 |
4 | 22202103231122133 |
5 | 141132112312320 |
6 | 5110325023503 |
7 | 550230000264 |
oct | 124223553237 |
9 | 32172373623 |
10 | 11313010335 |
11 | 4885999120 |
12 | 2238854b93 |
13 | 10b3a2c273 |
14 | 7946ad26b |
15 | 4632bd0e0 |
hex | 2a24ed69f |
11313010335 has 32 divisors (see below), whose sum is σ = 19754092800. Its totient is φ = 5482944000.
The previous prime is 11313010333. The next prime is 11313010337. The reversal of 11313010335 is 53301031311.
It is an interprime number because it is at equal distance from previous prime (11313010333) and next prime (11313010337).
It is not a de Polignac number, because 11313010335 - 21 = 11313010333 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11313010333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 458391 + ... + 482439.
It is an arithmetic number, because the mean of its divisors is an integer number (617315400).
Almost surely, 211313010335 is an apocalyptic number.
11313010335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11313010335 is a deficient number, since it is larger than the sum of its proper divisors (8441082465).
11313010335 is a wasteful number, since it uses less digits than its factorization.
11313010335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26919.
The product of its (nonzero) digits is 405, while the sum is 21.
Adding to 11313010335 its reverse (53301031311), we get a palindrome (64614041646).
The spelling of 11313010335 in words is "eleven billion, three hundred thirteen million, ten thousand, three hundred thirty-five".
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