Base | Representation |
---|---|
bin | 10101000100100111… |
… | …01111110100111011 |
3 | 1002012102102222020212 |
4 | 22202103233310323 |
5 | 141132113121334 |
6 | 5110325141335 |
7 | 550230041144 |
oct | 124223576473 |
9 | 32172388225 |
10 | 11313020219 |
11 | 48859a5596 |
12 | 223885a84b |
13 | 10b3a33907 |
14 | 7946b2acb |
15 | 4632c0ece |
hex | 2a24efd3b |
11313020219 has 2 divisors, whose sum is σ = 11313020220. Its totient is φ = 11313020218.
The previous prime is 11313020207. The next prime is 11313020239. The reversal of 11313020219 is 91202031311.
It is a weak prime.
It is an emirp because it is prime and its reverse (91202031311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11313020219 - 216 = 11312954683 is a prime.
It is a super-2 number, since 2×113130202192 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11313020194 and 11313020203.
It is not a weakly prime, because it can be changed into another prime (11313020239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656510109 + 5656510110.
It is an arithmetic number, because the mean of its divisors is an integer number (5656510110).
Almost surely, 211313020219 is an apocalyptic number.
11313020219 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313020219 is an equidigital number, since it uses as much as digits as its factorization.
11313020219 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 23.
The spelling of 11313020219 in words is "eleven billion, three hundred thirteen million, twenty thousand, two hundred nineteen".
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