Base | Representation |
---|---|
bin | 10101000100100111… |
… | …10011000000010001 |
3 | 1002012102110122002212 |
4 | 22202103303000101 |
5 | 141132114030413 |
6 | 5110325321505 |
7 | 550230124115 |
oct | 124223630021 |
9 | 32172418085 |
10 | 11313033233 |
11 | 4885a04347 |
12 | 2238866295 |
13 | 10b3a39808 |
14 | 7946b7745 |
15 | 4632c4ca8 |
hex | 2a24f3011 |
11313033233 has 2 divisors, whose sum is σ = 11313033234. Its totient is φ = 11313033232.
The previous prime is 11313033229. The next prime is 11313033239. The reversal of 11313033233 is 33233031311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7936493569 + 3376539664 = 89087^2 + 58108^2 .
It is a cyclic number.
It is not a de Polignac number, because 11313033233 - 22 = 11313033229 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11313033199 and 11313033208.
It is not a weakly prime, because it can be changed into another prime (11313033239) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656516616 + 5656516617.
It is an arithmetic number, because the mean of its divisors is an integer number (5656516617).
Almost surely, 211313033233 is an apocalyptic number.
It is an amenable number.
11313033233 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313033233 is an equidigital number, since it uses as much as digits as its factorization.
11313033233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 23.
Adding to 11313033233 its reverse (33233031311), we get a palindrome (44546064544).
The spelling of 11313033233 in words is "eleven billion, three hundred thirteen million, thirty-three thousand, two hundred thirty-three".
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