Base | Representation |
---|---|
bin | 10101000100101000… |
… | …00011010101000111 |
3 | 1002012102121000211112 |
4 | 22202110003111013 |
5 | 141132123200403 |
6 | 5110330555235 |
7 | 550230523064 |
oct | 124224032507 |
9 | 32172530745 |
10 | 11313100103 |
11 | 4885a4a608 |
12 | 2238898b1b |
13 | 10b3a61096 |
14 | 7946d3c6b |
15 | 4632d99d8 |
hex | 2a2503547 |
11313100103 has 4 divisors (see below), whose sum is σ = 11678038848. Its totient is φ = 10948161360.
The previous prime is 11313100063. The next prime is 11313100157. The reversal of 11313100103 is 30100131311.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11313100103 - 224 = 11296322887 is a prime.
It is a super-2 number, since 2×113131001032 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11313100163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 182469326 + ... + 182469387.
It is an arithmetic number, because the mean of its divisors is an integer number (2919509712).
Almost surely, 211313100103 is an apocalyptic number.
11313100103 is a deficient number, since it is larger than the sum of its proper divisors (364938745).
11313100103 is an equidigital number, since it uses as much as digits as its factorization.
11313100103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 364938744.
The product of its (nonzero) digits is 27, while the sum is 14.
Adding to 11313100103 its reverse (30100131311), we get a palindrome (41413231414).
The spelling of 11313100103 in words is "eleven billion, three hundred thirteen million, one hundred thousand, one hundred three".
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