1131310131283 has 2 divisors, whose sum is σ = 1131310131284. Its totient is φ = 1131310131282.

The previous prime is 1131310131269. The next prime is 1131310131317. The reversal of 1131310131283 is 3821310131311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1131310131283 - 2²⁹ = 1130773260371 is a prime.

It is a super-2 number, since 2×1131310131283² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1131310131223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565655065641 + 565655065642.

It is an arithmetic number, because the mean of its divisors is an integer number (565655065642).

Almost surely, 2^{1131310131283} is an apocalyptic number.

1131310131283 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131310131283 is an equidigital number, since it uses as much as digits as its factorization.

1131310131283 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 28.

Adding to 1131310131283 its sum of digits (28), we get a palindrome (1131310131311).

Adding to 1131310131283 its reverse (3821310131311), we get a palindrome (4952620262594).

The spelling of 1131310131283 in words is "one trillion, one hundred thirty-one billion, three hundred ten million, one hundred thirty-one thousand, two hundred eighty-three".