Base | Representation |
---|---|
bin | 110100101011100100… |
… | …0100100110000110111 |
3 | 101211000021222000210212 |
4 | 1221113020210300313 |
5 | 3323143014441343 |
6 | 123545514140035 |
7 | 11113330522502 |
oct | 1512710446067 |
9 | 354007860725 |
10 | 113131015223 |
11 | 43a845661a6 |
12 | 19b1342161b |
13 | a88c094035 |
14 | 5692d72139 |
15 | 2e21e1ac18 |
hex | 1a57224c37 |
113131015223 has 4 divisors (see below), whose sum is σ = 113184557808. Its totient is φ = 113077472640.
The previous prime is 113131015187. The next prime is 113131015229. The reversal of 113131015223 is 322510131311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 322510131311 = 19381 ⋅16640531.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113131015223 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113131015229) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26768123 + ... + 26772348.
It is an arithmetic number, because the mean of its divisors is an integer number (28296139452).
Almost surely, 2113131015223 is an apocalyptic number.
113131015223 is a deficient number, since it is larger than the sum of its proper divisors (53542585).
113131015223 is an equidigital number, since it uses as much as digits as its factorization.
113131015223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53542584.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 113131015223 its reverse (322510131311), we get a palindrome (435641146534).
The spelling of 113131015223 in words is "one hundred thirteen billion, one hundred thirty-one million, fifteen thousand, two hundred twenty-three".
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