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113131023193 is a prime number
BaseRepresentation
bin110100101011100100…
…0100110101101011001
3101211000021222102202001
41221113020212231121
53323143020220233
6123545514241001
711113330554646
oct1512710465531
9354007872661
10113131023193
1143a84571191
1219b13426161
13a88c097856
145692d74dcd
152e21e1d27d
hex1a57226b59

113131023193 has 2 divisors, whose sum is σ = 113131023194. Its totient is φ = 113131023192.

The previous prime is 113131023179. The next prime is 113131023211. The reversal of 113131023193 is 391320131311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100852610329 + 12278412864 = 317573^2 + 110808^2 .

It is an emirp because it is prime and its reverse (391320131311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113131023193 - 29 = 113131022681 is a prime.

It is not a weakly prime, because it can be changed into another prime (113131023113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56565511596 + 56565511597.

It is an arithmetic number, because the mean of its divisors is an integer number (56565511597).

Almost surely, 2113131023193 is an apocalyptic number.

It is an amenable number.

113131023193 is a deficient number, since it is larger than the sum of its proper divisors (1).

113131023193 is an equidigital number, since it uses as much as digits as its factorization.

113131023193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1458, while the sum is 28.

The spelling of 113131023193 in words is "one hundred thirteen billion, one hundred thirty-one million, twenty-three thousand, one hundred ninety-three".