Base | Representation |
---|---|
bin | 10000011101100111011… |
… | …001000001100111100011 |
3 | 11000011010000020222220211 |
4 | 100131213121001213203 |
5 | 122013411104343243 |
6 | 2223414521114551 |
7 | 144506640640522 |
oct | 20354731014743 |
9 | 4004100228824 |
10 | 1131311012323 |
11 | 3a6871633a88 |
12 | 163309928a57 |
13 | 828b39628bb |
14 | 3ca81a9c4b9 |
15 | 1e664742d9d |
hex | 107676419e3 |
1131311012323 has 2 divisors, whose sum is σ = 1131311012324. Its totient is φ = 1131311012322.
The previous prime is 1131311012267. The next prime is 1131311012369. The reversal of 1131311012323 is 3232101131311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1131311012323 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1131311012294 and 1131311012303.
It is not a weakly prime, because it can be changed into another prime (1131311012423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565655506161 + 565655506162.
It is an arithmetic number, because the mean of its divisors is an integer number (565655506162).
Almost surely, 21131311012323 is an apocalyptic number.
1131311012323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131311012323 is an equidigital number, since it uses as much as digits as its factorization.
1131311012323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 1131311012323 its reverse (3232101131311), we get a palindrome (4363412143634).
The spelling of 1131311012323 in words is "one trillion, one hundred thirty-one billion, three hundred eleven million, twelve thousand, three hundred twenty-three".
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