Search a number
-
+
11313119977 is a prime number
BaseRepresentation
bin10101000100101000…
…01000001011101001
31002012102122001002121
422202110020023221
5141132124314402
65110331231241
7550230635035
oct124224101351
932172561077
1011313119977
114885a63535
1222388a8521
1310b3a6a143
147946db1c5
154632e0837
hex2a25082e9

11313119977 has 2 divisors, whose sum is σ = 11313119978. Its totient is φ = 11313119976.

The previous prime is 11313119969. The next prime is 11313120017. The reversal of 11313119977 is 77991131311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9757290841 + 1555829136 = 98779^2 + 39444^2 .

It is a cyclic number.

It is not a de Polignac number, because 11313119977 - 23 = 11313119969 is a prime.

It is a super-2 number, since 2×113131199772 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11313119177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656559988 + 5656559989.

It is an arithmetic number, because the mean of its divisors is an integer number (5656559989).

Almost surely, 211313119977 is an apocalyptic number.

It is an amenable number.

11313119977 is a deficient number, since it is larger than the sum of its proper divisors (1).

11313119977 is an equidigital number, since it uses as much as digits as its factorization.

11313119977 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 35721, while the sum is 43.

The spelling of 11313119977 in words is "eleven billion, three hundred thirteen million, one hundred nineteen thousand, nine hundred seventy-seven".