Base | Representation |
---|---|
bin | 10101000100101000… |
… | …01000011011101011 |
3 | 1002012102122002111121 |
4 | 22202110020123223 |
5 | 141132124333003 |
6 | 5110331240111 |
7 | 550230641032 |
oct | 124224103353 |
9 | 32172562447 |
10 | 11313121003 |
11 | 4885a64288 |
12 | 22388a9037 |
13 | 10b3a6a752 |
14 | 7946db719 |
15 | 4632e0cbd |
hex | 2a25086eb |
11313121003 has 2 divisors, whose sum is σ = 11313121004. Its totient is φ = 11313121002.
The previous prime is 11313120979. The next prime is 11313121013. The reversal of 11313121003 is 30012131311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11313121003 is a prime.
It is not a weakly prime, because it can be changed into another prime (11313121013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656560501 + 5656560502.
It is an arithmetic number, because the mean of its divisors is an integer number (5656560502).
Almost surely, 211313121003 is an apocalyptic number.
11313121003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313121003 is an equidigital number, since it uses as much as digits as its factorization.
11313121003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 11313121003 its reverse (30012131311), we get a palindrome (41325252314).
The spelling of 11313121003 in words is "eleven billion, three hundred thirteen million, one hundred twenty-one thousand, three".
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