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1131312121220 = 22556565606061
BaseRepresentation
bin10000011101100111011…
…101010000010110000100
311000011010002100100001002
4100131213131100112010
5122013411400334340
62223415000552432
7144506653236461
oct20354735202604
94004102310032
101131312121220
113a6872221126
1216330a182718
13828b3c60558
143ca81caa668
151e6648b1715
hex10767750584

1131312121220 has 12 divisors (see below), whose sum is σ = 2375755454604. Its totient is φ = 452524848480.

The previous prime is 1131312121207. The next prime is 1131312121241. The reversal of 1131312121220 is 221212131311.

It can be written as a sum of positive squares in 2 ways, for example, as 836595598336 + 294716522884 = 914656^2 + 542878^2 .

It is a Harshad number since it is a multiple of its sum of digits (20), and also a Moran number because the ratio is a prime number: 56565606061 = 1131312121220 / (1 + 1 + 3 + 1 + 3 + 1 + 2 + 1 + 2 + 1 + 2 + 2 + 0).

It is a junction number, because it is equal to n+sod(n) for n = 1131312121192 and 1131312121201.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28282803011 + ... + 28282803050.

It is an arithmetic number, because the mean of its divisors is an integer number (197979621217).

Almost surely, 21131312121220 is an apocalyptic number.

1131312121220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1131312121220 is an abundant number, since it is smaller than the sum of its proper divisors (1244443333384).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1131312121220 is a wasteful number, since it uses less digits than its factorization.

1131312121220 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56565606070 (or 56565606068 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1131312121220 its reverse (221212131311), we get a palindrome (1352524252531).

The spelling of 1131312121220 in words is "one trillion, one hundred thirty-one billion, three hundred twelve million, one hundred twenty-one thousand, two hundred twenty".

Divisors: 1 2 4 5 10 20 56565606061 113131212122 226262424244 282828030305 565656060610 1131312121220