113131242001 has 2 divisors, whose sum is σ = 113131242002. Its totient is φ = 113131242000.

The previous prime is 113131241959. The next prime is 113131242013. The reversal of 113131242001 is 100242131311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 103590641025 + 9540600976 = 321855^2 + 97676^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113131242001 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 113131242001.

It is not a weakly prime, because it can be changed into another prime (113131242401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56565621000 + 56565621001.

It is an arithmetic number, because the mean of its divisors is an integer number (56565621001).

Almost surely, 2^113131242001 is an apocalyptic number.

It is an amenable number.

113131242001 is a deficient number, since it is larger than the sum of its proper divisors (1).

113131242001 is an equidigital number, since it uses as much as digits as its factorization.

113131242001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 113131242001 its reverse (100242131311), we get a palindrome (213373373312).

The spelling of 113131242001 in words is "one hundred thirteen billion, one hundred thirty-one million, two hundred forty-two thousand, one".