Base | Representation |
---|---|
bin | 110100101011100100… |
… | …1110010000110101011 |
3 | 101211000022120010100202 |
4 | 1221113021302012223 |
5 | 3323143110111021 |
6 | 123545525022415 |
7 | 11113333312205 |
oct | 1512711620653 |
9 | 354008503322 |
10 | 113131332011 |
11 | 43a84762205 |
12 | 19b13554a0b |
13 | a88c175299 |
14 | 5693015775 |
15 | 2e21e7ea0b |
hex | 1a572721ab |
113131332011 has 2 divisors, whose sum is σ = 113131332012. Its totient is φ = 113131332010.
The previous prime is 113131331933. The next prime is 113131332071. The reversal of 113131332011 is 110233131311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113131332011 is a prime.
It is a super-2 number, since 2×1131313320112 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (113131332071) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56565666005 + 56565666006.
It is an arithmetic number, because the mean of its divisors is an integer number (56565666006).
Almost surely, 2113131332011 is an apocalyptic number.
113131332011 is a deficient number, since it is larger than the sum of its proper divisors (1).
113131332011 is an equidigital number, since it uses as much as digits as its factorization.
113131332011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 113131332011 its reverse (110233131311), we get a palindrome (223364463322).
The spelling of 113131332011 in words is "one hundred thirteen billion, one hundred thirty-one million, three hundred thirty-two thousand, eleven".
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