113131400153 has 2 divisors, whose sum is σ = 113131400154. Its totient is φ = 113131400152.

The previous prime is 113131400113. The next prime is 113131400159. The reversal of 113131400153 is 351004131311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 74197401664 + 38933998489 = 272392^2 + 197317^2 .

It is an emirp because it is prime and its reverse (351004131311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113131400153 - 2²⁴ = 113114622937 is a prime.

It is not a weakly prime, because it can be changed into another prime (113131400159) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56565700076 + 56565700077.

It is an arithmetic number, because the mean of its divisors is an integer number (56565700077).

Almost surely, 2^113131400153 is an apocalyptic number.

It is an amenable number.

113131400153 is a deficient number, since it is larger than the sum of its proper divisors (1).

113131400153 is an equidigital number, since it uses as much as digits as its factorization.

113131400153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 113131400153 its reverse (351004131311), we get a palindrome (464135531464).

The spelling of 113131400153 in words is "one hundred thirteen billion, one hundred thirty-one million, four hundred thousand, one hundred fifty-three".