1131314313132 has 120 divisors (see below), whose sum is σ = 2990153692064. Its totient is φ = 372944176128.

The previous prime is 1131314313121. The next prime is 1131314313169. The reversal of 1131314313132 is 2313134131311.

1131314313132 is a `hidden beast` number, since 1 + 1 + 3 + 1 + 314 + 31 + 313 + 2 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a nude number because it is divisible by every one of its digits.

It is a junction number, because it is equal to n+sod(n) for n = 1131314313096 and 1131314313105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 45463878 + ... + 45488754.

Almost surely, 2^{1131314313132} is an apocalyptic number.

1131314313132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1131314313132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1495076846032).

1131314313132 is an abundant number, since it is smaller than the sum of its proper divisors (1858839378932).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1131314313132 is a wasteful number, since it uses less digits than its factorization.

1131314313132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26437 (or 26426 counting only the distinct ones).

The product of its digits is 1944, while the sum is 27.

Adding to 1131314313132 its reverse (2313134131311), we get a palindrome (3444448444443).

The spelling of 1131314313132 in words is "one trillion, one hundred thirty-one billion, three hundred fourteen million, three hundred thirteen thousand, one hundred thirty-two".