113131441141 has 4 divisors (see below), whose sum is σ = 113133540672. Its totient is φ = 113129341612.

The previous prime is 113131441139. The next prime is 113131441187. The reversal of 113131441141 is 141144131311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113131441141 - 2¹ = 113131441139 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113131441541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 966751 + ... + 1077436.

It is an arithmetic number, because the mean of its divisors is an integer number (28283385168).

Almost surely, 2^113131441141 is an apocalyptic number.

It is an amenable number.

113131441141 is a deficient number, since it is larger than the sum of its proper divisors (2099531).

113131441141 is an equidigital number, since it uses as much as digits as its factorization.

113131441141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2099530.

The product of its digits is 576, while the sum is 25.

Adding to 113131441141 its reverse (141144131311), we get a palindrome (254275572452).

The spelling of 113131441141 in words is "one hundred thirteen billion, one hundred thirty-one million, four hundred forty-one thousand, one hundred forty-one".