Base | Representation |
---|---|
bin | 1010010010100000111101… |
… | …0101110001010110111111 |
3 | 1111001112100110000022201112 |
4 | 2210220033111301112333 |
5 | 2440323414003114403 |
6 | 40021113552432235 |
7 | 2245231446513623 |
oct | 244501725612677 |
9 | 44045313008645 |
10 | 11313201223103 |
11 | 36719a117954a |
12 | 13286a824867b |
13 | 640aa4219580 |
14 | 2b17c1a63183 |
15 | 149437cb69d8 |
hex | a4a0f5715bf |
11313201223103 has 16 divisors (see below), whose sum is σ = 12748819106016. Its totient is φ = 9969001361280.
The previous prime is 11313201223073. The next prime is 11313201223117. The reversal of 11313201223103 is 30132210231311.
It is not a de Polignac number, because 11313201223103 - 26 = 11313201223039 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11313201223153) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 221862893 + ... + 221913878.
It is an arithmetic number, because the mean of its divisors is an integer number (796801194126).
Almost surely, 211313201223103 is an apocalyptic number.
11313201223103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11313201223103 is a deficient number, since it is larger than the sum of its proper divisors (1435617882913).
11313201223103 is a wasteful number, since it uses less digits than its factorization.
11313201223103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 443776874.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 11313201223103 its reverse (30132210231311), we get a palindrome (41445411454414).
The spelling of 11313201223103 in words is "eleven trillion, three hundred thirteen billion, two hundred one million, two hundred twenty-three thousand, one hundred three".
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