113132017 has 2 divisors, whose sum is σ = 113132018. Its totient is φ = 113132016.

The previous prime is 113131999. The next prime is 113132027. The reversal of 113132017 is 710231311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85211361 + 27920656 = 9231^2 + 5284^2 .

It is an emirp because it is prime and its reverse (710231311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113132017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113131985 and 113132003.

It is not a weakly prime, because it can be changed into another prime (113132027) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56566008 + 56566009.

It is an arithmetic number, because the mean of its divisors is an integer number (56566009).

Almost surely, 2^113132017 is an apocalyptic number.

It is an amenable number.

113132017 is a deficient number, since it is larger than the sum of its proper divisors (1).

113132017 is an equidigital number, since it uses as much as digits as its factorization.

113132017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 126, while the sum is 19.

The square root of 113132017 is about 10636.3535574933. The cubic root of 113132017 is about 483.6470131326.

Adding to 113132017 its reverse (710231311), we get a palindrome (823363328).

The spelling of 113132017 in words is "one hundred thirteen million, one hundred thirty-two thousand, seventeen".