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11313210014120 = 235731247998761
BaseRepresentation
bin1010010010100000111111…
…0111010011100110101000
31111001112101001112221201202
42210220033313103212220
52440323423230422440
640021114505103332
72245231614316460
oct244501767234650
944045331487652
1011313210014120
1136719a6133353
1213286ab187b48
13640aa5ca6a61
142b17c2cb0ba0
15149438951615
hexa4a0fdd39a8

11313210014120 has 192 divisors, whose sum is σ = 30069501696000. Its totient is φ = 3752481254400.

The previous prime is 11313210014009. The next prime is 11313210014137. The reversal of 11313210014120 is 2141001231311.

11313210014120 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 11313210014092 and 11313210014101.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1291310540 + ... + 1291319300.

It is an arithmetic number, because the mean of its divisors is an integer number (156611988000).

Almost surely, 211313210014120 is an apocalyptic number.

11313210014120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11313210014120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15034750848000).

11313210014120 is an abundant number, since it is smaller than the sum of its proper divisors (18756291681880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11313210014120 is a wasteful number, since it uses less digits than its factorization.

11313210014120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13640 (or 13605 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 11313210014120 its reverse (2141001231311), we get a palindrome (13454211245431).

The spelling of 11313210014120 in words is "eleven trillion, three hundred thirteen billion, two hundred ten million, fourteen thousand, one hundred twenty".