Base | Representation |
---|---|
bin | 1010010010100000111111… |
… | …1000011011111010111011 |
3 | 1111001112101002010000001112 |
4 | 2210220033320123322323 |
5 | 2440323423314412311 |
6 | 40021114515310535 |
7 | 2245231616662166 |
oct | 244501770337273 |
9 | 44045332100045 |
10 | 11313210310331 |
11 | 36719a6315956 |
12 | 13286ab2ab44b |
13 | 640aa607b827 |
14 | 2b17c2d4aadd |
15 | 1494389ae28b |
hex | a4a0fe1bebb |
11313210310331 has 2 divisors, whose sum is σ = 11313210310332. Its totient is φ = 11313210310330.
The previous prime is 11313210310273. The next prime is 11313210310373. The reversal of 11313210310331 is 13301301231311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11313210310331 - 222 = 11313206116027 is a prime.
It is a super-2 number, since 2×113132103103312 (a number of 27 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 11313210310297 and 11313210310306.
It is not a weakly prime, because it can be changed into another prime (11313210310231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656605155165 + 5656605155166.
It is an arithmetic number, because the mean of its divisors is an integer number (5656605155166).
Almost surely, 211313210310331 is an apocalyptic number.
11313210310331 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313210310331 is an equidigital number, since it uses as much as digits as its factorization.
11313210310331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 11313210310331 its reverse (13301301231311), we get a palindrome (24614511541642).
The spelling of 11313210310331 in words is "eleven trillion, three hundred thirteen billion, two hundred ten million, three hundred ten thousand, three hundred thirty-one".
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