Base | Representation |
---|---|
bin | 10101000100101000… |
… | …11110111011000010 |
3 | 1002012102210202212102 |
4 | 22202110132323002 |
5 | 141132140304442 |
6 | 5110333230402 |
7 | 550231503431 |
oct | 124224367302 |
9 | 32172722772 |
10 | 11313213122 |
11 | 4886017512 |
12 | 2238932402 |
13 | 10b3aa0663 |
14 | 794723118 |
15 | 46330d232 |
hex | 2a251eec2 |
11313213122 has 4 divisors (see below), whose sum is σ = 16969819686. Its totient is φ = 5656606560.
The previous prime is 11313213089. The next prime is 11313213127. The reversal of 11313213122 is 22131231311.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 6766543081 + 4546670041 = 82259^2 + 67429^2 .
It is a super-2 number, since 2×113132131222 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11313213094 and 11313213103.
It is not an unprimeable number, because it can be changed into a prime (11313213127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2828303279 + ... + 2828303282.
Almost surely, 211313213122 is an apocalyptic number.
11313213122 is a deficient number, since it is larger than the sum of its proper divisors (5656606564).
11313213122 is an equidigital number, since it uses as much as digits as its factorization.
11313213122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5656606563.
The product of its digits is 216, while the sum is 20.
Adding to 11313213122 its reverse (22131231311), we get a palindrome (33444444433).
The spelling of 11313213122 in words is "eleven billion, three hundred thirteen million, two hundred thirteen thousand, one hundred twenty-two".
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