Base | Representation |
---|---|
bin | 10000011101101000000… |
… | …000010110001001111001 |
3 | 11000011010201122200110202 |
4 | 100131220000112021321 |
5 | 122013421224220212 |
6 | 2223415530051545 |
7 | 144510124361315 |
oct | 20355000261171 |
9 | 4004121580422 |
10 | 1131321320057 |
11 | 3a6877434375 |
12 | 163311279bb5 |
13 | 828b5b31556 |
14 | 3ca831c2b45 |
15 | 1e6655cc0c2 |
hex | 10768016279 |
1131321320057 has 2 divisors, whose sum is σ = 1131321320058. Its totient is φ = 1131321320056.
The previous prime is 1131321320021. The next prime is 1131321320071. The reversal of 1131321320057 is 7500231231311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 854877763216 + 276443556841 = 924596^2 + 525779^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131321320057 - 210 = 1131321319033 is a prime.
It is not a weakly prime, because it can be changed into another prime (1131321320357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565660660028 + 565660660029.
It is an arithmetic number, because the mean of its divisors is an integer number (565660660029).
Almost surely, 21131321320057 is an apocalyptic number.
It is an amenable number.
1131321320057 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131321320057 is an equidigital number, since it uses as much as digits as its factorization.
1131321320057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3780, while the sum is 29.
Adding to 1131321320057 its reverse (7500231231311), we get a palindrome (8631552551368).
The spelling of 1131321320057 in words is "one trillion, one hundred thirty-one billion, three hundred twenty-one million, three hundred twenty thousand, fifty-seven".
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