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11313215450142 = 231885535908357
BaseRepresentation
bin1010010010100001000000…
…1100000010110000011110
31111001112101102210010112220
42210220100030002300132
52440323431123401032
640021115221410210
72245232011450104
oct244502014026036
944045342703486
1011313215450142
1136719a9206531
1213286b0b69966
13640aa715b138
142b17c38c7c74
1514943917712c
hexa4a10302c1e

11313215450142 has 8 divisors (see below), whose sum is σ = 22626430900296. Its totient is φ = 3771071816712.

The previous prime is 11313215450129. The next prime is 11313215450161. The reversal of 11313215450142 is 24105451231311.

It is a sphenic number, since it is the product of 3 distinct primes.

11313215450142 is an admirable number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 942767954173 + ... + 942767954184.

It is an arithmetic number, because the mean of its divisors is an integer number (2828303862537).

Almost surely, 211313215450142 is an apocalyptic number.

11313215450142 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11313215450142 is a wasteful number, since it uses less digits than its factorization.

11313215450142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1885535908362.

The product of its (nonzero) digits is 14400, while the sum is 33.

Adding to 11313215450142 its reverse (24105451231311), we get a palindrome (35418666681453).

The spelling of 11313215450142 in words is "eleven trillion, three hundred thirteen billion, two hundred fifteen million, four hundred fifty thousand, one hundred forty-two".

Divisors: 1 2 3 6 1885535908357 3771071816714 5656607725071 11313215450142