Base | Representation |
---|---|
bin | 10101000100101001… |
… | …00001011010000111 |
3 | 1002012102211021211111 |
4 | 22202110201122013 |
5 | 141132141121203 |
6 | 5110333345451 |
7 | 550231545214 |
oct | 124224413207 |
9 | 32172737744 |
10 | 11313223303 |
11 | 4886024128 |
12 | 2238938287 |
13 | 10b3aa5195 |
14 | 794726b0b |
15 | 46331126d |
hex | 2a2521687 |
11313223303 has 4 divisors (see below), whose sum is σ = 11345826600. Its totient is φ = 11280620008.
The previous prime is 11313223231. The next prime is 11313223307. The reversal of 11313223303 is 30332231311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30332231311 = 541 ⋅56066971.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11313223303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11313223307) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16301128 + ... + 16301821.
It is an arithmetic number, because the mean of its divisors is an integer number (2836456650).
Almost surely, 211313223303 is an apocalyptic number.
11313223303 is a deficient number, since it is larger than the sum of its proper divisors (32603297).
11313223303 is an equidigital number, since it uses as much as digits as its factorization.
11313223303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32603296.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 11313223303 its reverse (30332231311), we get a palindrome (41645454614).
The spelling of 11313223303 in words is "eleven billion, three hundred thirteen million, two hundred twenty-three thousand, three hundred three".
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