Base | Representation |
---|---|
bin | 10101000100101001… |
… | …00001111001101001 |
3 | 1002012102211101121020 |
4 | 22202110201321221 |
5 | 141132141202241 |
6 | 5110333403053 |
7 | 550231554126 |
oct | 124224417151 |
9 | 32172741536 |
10 | 11313225321 |
11 | 48860256a2 |
12 | 2238939489 |
13 | 10b3aa6088 |
14 | 79472774d |
15 | 463311b66 |
hex | 2a2521e69 |
11313225321 has 4 divisors (see below), whose sum is σ = 15084300432. Its totient is φ = 7542150212.
The previous prime is 11313225311. The next prime is 11313225323. The reversal of 11313225321 is 12352231311.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11313225321 - 25 = 11313225289 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11313225291 and 11313225300.
It is not an unprimeable number, because it can be changed into a prime (11313225323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1885537551 + ... + 1885537556.
It is an arithmetic number, because the mean of its divisors is an integer number (3771075108).
Almost surely, 211313225321 is an apocalyptic number.
It is an amenable number.
11313225321 is a deficient number, since it is larger than the sum of its proper divisors (3771075111).
11313225321 is an equidigital number, since it uses as much as digits as its factorization.
11313225321 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3771075110.
The product of its digits is 1080, while the sum is 24.
Adding to 11313225321 its reverse (12352231311), we get a palindrome (23665456632).
The spelling of 11313225321 in words is "eleven billion, three hundred thirteen million, two hundred twenty-five thousand, three hundred twenty-one".
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