Base | Representation |
---|---|
bin | 10000011101101000000… |
… | …111001011101001100001 |
3 | 11000011010212000201121020 |
4 | 100131220013023221201 |
5 | 122013422204041113 |
6 | 2223420032320053 |
7 | 144510145533612 |
oct | 20355007135141 |
9 | 4004125021536 |
10 | 1131323112033 |
11 | 3a6878448744 |
12 | 1633119a3029 |
13 | 828b630b0aa |
14 | 3ca8352bc09 |
15 | 1e665833023 |
hex | 107681cba61 |
1131323112033 has 8 divisors (see below), whose sum is σ = 1514166295488. Its totient is φ = 751347668304.
The previous prime is 1131323112013. The next prime is 1131323112037. The reversal of 1131323112033 is 3302113231311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1131323112033 - 214 = 1131323095649 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1131323111994 and 1131323112012.
It is not an unprimeable number, because it can be changed into a prime (1131323112037) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 716934010 + ... + 716935587.
It is an arithmetic number, because the mean of its divisors is an integer number (189270786936).
Almost surely, 21131323112033 is an apocalyptic number.
It is an amenable number.
1131323112033 is a deficient number, since it is larger than the sum of its proper divisors (382843183455).
1131323112033 is a wasteful number, since it uses less digits than its factorization.
1131323112033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1433869863.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 1131323112033 its reverse (3302113231311), we get a palindrome (4433436343344).
The spelling of 1131323112033 in words is "one trillion, one hundred thirty-one billion, three hundred twenty-three million, one hundred twelve thousand, thirty-three".
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