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1131323331013 = 2699419163887
BaseRepresentation
bin10000011101101000001…
…000000001000111000101
311000011010212102211222121
4100131220020001013011
5122013422233043023
62223420041125541
7144510150435211
oct20355010010705
94004125384877
101131323331013
113a6878588217
12163311a898b1
13828b6386975
143ca83587941
151e665877d5d
hex107682011c5

1131323331013 has 4 divisors (see below), whose sum is σ = 1131742497600. Its totient is φ = 1130904164428.

The previous prime is 1131323331007. The next prime is 1131323331071. The reversal of 1131323331013 is 3101333231311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1131323331013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131323331613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 209579245 + ... + 209584642.

It is an arithmetic number, because the mean of its divisors is an integer number (282935624400).

Almost surely, 21131323331013 is an apocalyptic number.

It is an amenable number.

1131323331013 is a deficient number, since it is larger than the sum of its proper divisors (419166587).

1131323331013 is an equidigital number, since it uses as much as digits as its factorization.

1131323331013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 419166586.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 1131323331013 its reverse (3101333231311), we get a palindrome (4232656562324).

The spelling of 1131323331013 in words is "one trillion, one hundred thirty-one billion, three hundred twenty-three million, three hundred thirty-one thousand, thirteen".

Divisors: 1 2699 419163887 1131323331013