Base | Representation |
---|---|
bin | 10101000100101001… |
… | …00101101000011011 |
3 | 1002012102212011120020 |
4 | 22202110211220123 |
5 | 141132142144403 |
6 | 5110334001523 |
7 | 550231646520 |
oct | 124224455033 |
9 | 32172764506 |
10 | 11313240603 |
11 | 4886036125 |
12 | 22389462a3 |
13 | 10b3ab0012 |
14 | 79472d147 |
15 | 463316453 |
hex | 2a2525a1b |
11313240603 has 8 divisors (see below), whose sum is σ = 17239223808. Its totient is φ = 6464708904.
The previous prime is 11313240571. The next prime is 11313240629. The reversal of 11313240603 is 30604231311.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11313240603 - 25 = 11313240571 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11313240203) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 269362851 + ... + 269362892.
It is an arithmetic number, because the mean of its divisors is an integer number (2154902976).
Almost surely, 211313240603 is an apocalyptic number.
11313240603 is a deficient number, since it is larger than the sum of its proper divisors (5925983205).
11313240603 is an equidigital number, since it uses as much as digits as its factorization.
11313240603 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 538725753.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 11313240603 its reverse (30604231311), we get a palindrome (41917471914).
It can be divided in two parts, 113132 and 40603, that added together give a triangular number (153735 = T554).
The spelling of 11313240603 in words is "eleven billion, three hundred thirteen million, two hundred forty thousand, six hundred three".
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