Base | Representation |
---|---|
bin | 10101000100101001… |
… | …00101110001111100 |
3 | 1002012102212012101210 |
4 | 22202110211301330 |
5 | 141132142204322 |
6 | 5110334004420 |
7 | 550231651350 |
oct | 124224456174 |
9 | 32172765353 |
10 | 11313241212 |
11 | 4886036629 |
12 | 2238946710 |
13 | 10b3ab0390 |
14 | 79472d460 |
15 | 46331670c |
hex | 2a2525c7c |
11313241212 has 192 divisors, whose sum is σ = 35125959680. Its totient is φ = 2750091264.
The previous prime is 11313241207. The next prime is 11313241217. The reversal of 11313241212 is 21214231311.
It is an interprime number because it is at equal distance from previous prime (11313241207) and next prime (11313241217).
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a nude number because it is divisible by every one of its digits.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11313241217) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 760308 + ... + 775044.
Almost surely, 211313241212 is an apocalyptic number.
11313241212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11313241212, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17562979840).
11313241212 is an abundant number, since it is smaller than the sum of its proper divisors (23812718468).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11313241212 is a wasteful number, since it uses less digits than its factorization.
11313241212 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14820 (or 14818 counting only the distinct ones).
The product of its digits is 288, while the sum is 21.
Adding to 11313241212 its reverse (21214231311), we get a palindrome (32527472523).
Subtracting 11313241212 from its reverse (21214231311), we obtain a palindrome (9900990099).
The spelling of 11313241212 in words is "eleven billion, three hundred thirteen million, two hundred forty-one thousand, two hundred twelve".
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