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11313300321131 is a prime number
BaseRepresentation
bin1010010010100001010100…
…1111110011001101101011
31111001112121100111000122212
42210220111033303031223
52440324114340234011
640021131452435335
72245234062031304
oct244502517631553
944045540430585
1011313300321131
113671a42104346
121328715478b4b
13640abb905663
142b17d0c9b7ab
1514944183e08b
hexa4a153f336b

11313300321131 has 2 divisors, whose sum is σ = 11313300321132. Its totient is φ = 11313300321130.

The previous prime is 11313300321107. The next prime is 11313300321143. The reversal of 11313300321131 is 13112300331311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11313300321131 - 26 = 11313300321067 is a prime.

It is a super-2 number, since 2×113133003211312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11313300321097 and 11313300321106.

It is not a weakly prime, because it can be changed into another prime (11313300321161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656650160565 + 5656650160566.

It is an arithmetic number, because the mean of its divisors is an integer number (5656650160566).

Almost surely, 211313300321131 is an apocalyptic number.

11313300321131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11313300321131 is an equidigital number, since it uses as much as digits as its factorization.

11313300321131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 11313300321131 its reverse (13112300331311), we get a palindrome (24425600652442).

The spelling of 11313300321131 in words is "eleven trillion, three hundred thirteen billion, three hundred million, three hundred twenty-one thousand, one hundred thirty-one".