Base | Representation |
---|---|
bin | 1010010010100001010101… |
… | …0010011011111000100011 |
3 | 1111001112121101210010100201 |
4 | 2210220111102123320203 |
5 | 2440324120024341003 |
6 | 40021131515330031 |
7 | 2245234100636434 |
oct | 244502522337043 |
9 | 44045541703321 |
10 | 11313301012003 |
11 | 3671a42536411 |
12 | 1328715750917 |
13 | 640abbab7c63 |
14 | 2b17d0ddb48b |
15 | 149441928b1d |
hex | a4a1549be23 |
11313301012003 has 2 divisors, whose sum is σ = 11313301012004. Its totient is φ = 11313301012002.
The previous prime is 11313301011997. The next prime is 11313301012147. The reversal of 11313301012003 is 30021010331311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11313301012003 - 213 = 11313301003811 is a prime.
It is not a weakly prime, because it can be changed into another prime (11313301712003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656650506001 + 5656650506002.
It is an arithmetic number, because the mean of its divisors is an integer number (5656650506002).
Almost surely, 211313301012003 is an apocalyptic number.
11313301012003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313301012003 is an equidigital number, since it uses as much as digits as its factorization.
11313301012003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 11313301012003 its reverse (30021010331311), we get a palindrome (41334311343314).
The spelling of 11313301012003 in words is "eleven trillion, three hundred thirteen billion, three hundred one million, twelve thousand, three".
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