Base | Representation |
---|---|
bin | 1010010010100001010111… |
… | …1001101110110001101011 |
3 | 1111001112122010011110200020 |
4 | 2210220111321232301223 |
5 | 2440324130144004003 |
6 | 40021132524211523 |
7 | 2245234254331500 |
oct | 244502571566153 |
9 | 44045563143606 |
10 | 11313311313003 |
11 | 3671a48331737 |
12 | 1328719099ba3 |
13 | 640ac0c8381b |
14 | 2b17d251d4a7 |
15 | 1494427b0d53 |
hex | a4a15e6ec6b |
11313311313003 has 48 divisors (see below), whose sum is σ = 18163461065760. Its totient is φ = 6237972518400.
The previous prime is 11313311312993. The next prime is 11313311313023. The reversal of 11313311313003 is 30031311331311.
It is not a de Polignac number, because 11313311313003 - 29 = 11313311312491 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11313311313023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 6091743 + ... + 7728903.
It is an arithmetic number, because the mean of its divisors is an integer number (378405438870).
Almost surely, 211313311313003 is an apocalyptic number.
11313311313003 is a deficient number, since it is larger than the sum of its proper divisors (6850149752757).
11313311313003 is a wasteful number, since it uses less digits than its factorization.
11313311313003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1638828 (or 1638821 counting only the distinct ones).
The product of its (nonzero) digits is 729, while the sum is 24.
Adding to 11313311313003 its reverse (30031311331311), we get a palindrome (41344622644314).
The spelling of 11313311313003 in words is "eleven trillion, three hundred thirteen billion, three hundred eleven million, three hundred thirteen thousand, three".
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