Base | Representation |
---|---|
bin | 10101000100101001… |
… | …10111010011101001 |
3 | 1002012102222211212122 |
4 | 22202110313103221 |
5 | 141132202004001 |
6 | 5110335321025 |
7 | 550232400554 |
oct | 124224672351 |
9 | 32172884778 |
10 | 11313313001 |
11 | 4886085561 |
12 | 2238980175 |
13 | 10b3b06c63 |
14 | 79474b69b |
15 | 46332cb1b |
hex | 2a25374e9 |
11313313001 has 2 divisors, whose sum is σ = 11313313002. Its totient is φ = 11313313000.
The previous prime is 11313312929. The next prime is 11313313009. The reversal of 11313313001 is 10031331311.
11313313001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8364931600 + 2948381401 = 91460^2 + 54299^2 .
It is a cyclic number.
It is not a de Polignac number, because 11313313001 - 218 = 11313050857 is a prime.
It is not a weakly prime, because it can be changed into another prime (11313313009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656656500 + 5656656501.
It is an arithmetic number, because the mean of its divisors is an integer number (5656656501).
Almost surely, 211313313001 is an apocalyptic number.
It is an amenable number.
11313313001 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313313001 is an equidigital number, since it uses as much as digits as its factorization.
11313313001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 11313313001 its reverse (10031331311), we get a palindrome (21344644312).
The spelling of 11313313001 in words is "eleven billion, three hundred thirteen million, three hundred thirteen thousand, one".
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