Base | Representation |
---|---|
bin | 10101000100101001… |
… | …10111011010100000 |
3 | 1002012102222212110220 |
4 | 22202110313122200 |
5 | 141132202012230 |
6 | 5110335323040 |
7 | 550232402052 |
oct | 124224673240 |
9 | 32172885426 |
10 | 11313313440 |
11 | 4886085920 |
12 | 2238980480 |
13 | 10b3b07210 |
14 | 79474b8d2 |
15 | 46332cd10 |
hex | 2a25376a0 |
11313313440 has 192 divisors, whose sum is σ = 41867425152. Its totient is φ = 2531635200.
The previous prime is 11313313387. The next prime is 11313313447. The reversal of 11313313440 is 4431331311.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a self number, because there is not a number n which added to its sum of digits gives 11313313440.
It is not an unprimeable number, because it can be changed into a prime (11313313447) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13771 + ... + 151050.
It is an arithmetic number, because the mean of its divisors is an integer number (218059506).
Almost surely, 211313313440 is an apocalyptic number.
11313313440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11313313440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20933712576).
11313313440 is an abundant number, since it is smaller than the sum of its proper divisors (30554111712).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11313313440 is a wasteful number, since it uses less digits than its factorization.
11313313440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 164863 (or 164855 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 11313313440 its reverse (4431331311), we get a palindrome (15744644751).
It can be divided in two parts, 1131331 and 3440, that added together give a triangular number (1134771 = T1506).
The spelling of 11313313440 in words is "eleven billion, three hundred thirteen million, three hundred thirteen thousand, four hundred forty".
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