Base | Representation |
---|---|
bin | 11001101110010011100110… |
… | …111000010111001011001011 |
3 | 112211120102212001001222202011 |
4 | 121232103212320113023023 |
5 | 104312034010400030212 |
6 | 1040340420500320351 |
7 | 32554416640155325 |
oct | 3156234670271313 |
9 | 484512761058664 |
10 | 113133312111307 |
11 | 33058628342274 |
12 | 10831bb13a30b7 |
13 | 4b1856bc38a57 |
14 | 1dd1978152615 |
15 | d12ccc9614a7 |
hex | 66e4e6e172cb |
113133312111307 has 2 divisors, whose sum is σ = 113133312111308. Its totient is φ = 113133312111306.
The previous prime is 113133312111283. The next prime is 113133312111353. The reversal of 113133312111307 is 703111213331311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113133312111307 - 215 = 113133312078539 is a prime.
It is not a weakly prime, because it can be changed into another prime (113133312111707) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56566656055653 + 56566656055654.
It is an arithmetic number, because the mean of its divisors is an integer number (56566656055654).
Almost surely, 2113133312111307 is an apocalyptic number.
113133312111307 is a deficient number, since it is larger than the sum of its proper divisors (1).
113133312111307 is an equidigital number, since it uses as much as digits as its factorization.
113133312111307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3402, while the sum is 31.
Adding to 113133312111307 its reverse (703111213331311), we get a palindrome (816244525442618).
The spelling of 113133312111307 in words is "one hundred thirteen trillion, one hundred thirty-three billion, three hundred twelve million, one hundred eleven thousand, three hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.156 sec. • engine limits •