Base | Representation |
---|---|
bin | 1010010010100001110010… |
… | …0001100111001111101011 |
3 | 1111001112220212020212012102 |
4 | 2210220130201213033223 |
5 | 2440324342120244321 |
6 | 40021151534004015 |
7 | 2245240103661335 |
oct | 244503441471753 |
9 | 44045825225172 |
10 | 11313422431211 |
11 | 3671aa502746a |
12 | 132874a34660b |
13 | 640b0acbab44 |
14 | 2b18031a6455 |
15 | 14944c40ec0b |
hex | a4a1c8673eb |
11313422431211 has 2 divisors, whose sum is σ = 11313422431212. Its totient is φ = 11313422431210.
The previous prime is 11313422431187. The next prime is 11313422431231. The reversal of 11313422431211 is 11213422431311.
11313422431211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (11213422431311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11313422431211 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (11313422431231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656711215605 + 5656711215606.
It is an arithmetic number, because the mean of its divisors is an integer number (5656711215606).
Almost surely, 211313422431211 is an apocalyptic number.
11313422431211 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313422431211 is an equidigital number, since it uses as much as digits as its factorization.
11313422431211 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3456, while the sum is 29.
Adding to 11313422431211 its reverse (11213422431311), we get a palindrome (22526844862522).
The spelling of 11313422431211 in words is "eleven trillion, three hundred thirteen billion, four hundred twenty-two million, four hundred thirty-one thousand, two hundred eleven".
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