11313434240333 has 4 divisors (see below), whose sum is σ = 11337053101440. Its totient is φ = 11289815379228.

The previous prime is 11313434240323. The next prime is 11313434240341. The reversal of 11313434240333 is 33304243431311.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11313434240333 - 2²² = 11313430046029 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11313434240293 and 11313434240302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11313434240323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11809429835 + ... + 11809430792.

It is an arithmetic number, because the mean of its divisors is an integer number (2834263275360).

Almost surely, 2^{11313434240333} is an apocalyptic number.

It is an amenable number.

11313434240333 is a deficient number, since it is larger than the sum of its proper divisors (23618861107).

11313434240333 is an equidigital number, since it uses as much as digits as its factorization.

11313434240333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23618861106.

The product of its (nonzero) digits is 93312, while the sum is 35.

Adding to 11313434240333 its reverse (33304243431311), we get a palindrome (44617677671644).

The spelling of 11313434240333 in words is "eleven trillion, three hundred thirteen billion, four hundred thirty-four million, two hundred forty thousand, three hundred thirty-three".