11313434354112 has 252 divisors, whose sum is σ = 35650503364840. Its totient is φ = 3427679185920.

The previous prime is 11313434354107. The next prime is 11313434354113. The reversal of 11313434354112 is 21145343431311.

11313434354112 is a `hidden beast` number, since 1 + 1 + 31 + 3 + 43 + 43 + 541 + 1 + 2 = 666.

It is a super-2 number, since 2×11313434354112² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11313434354113) by changing a digit.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 492669543 + ... + 492692505.

Almost surely, 2^{11313434354112} is an apocalyptic number.

11313434354112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11313434354112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17825251682420).

11313434354112 is an abundant number, since it is smaller than the sum of its proper divisors (24337069010728).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11313434354112 is a wasteful number, since it uses less digits than its factorization.

11313434354112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30072 (or 30048 counting only the distinct ones).

The product of its digits is 51840, while the sum is 36.

Adding to 11313434354112 its reverse (21145343431311), we get a palindrome (32458777785423).

The spelling of 11313434354112 in words is "eleven trillion, three hundred thirteen billion, four hundred thirty-four million, three hundred fifty-four thousand, one hundred twelve".