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113136110143 = 722308900207
BaseRepresentation
bin110100101011101110…
…0000000101000111111
3101211000122112212201121
41221113130000220333
53323200321011033
6123550215251411
711113422032500
oct1512734005077
9354018485647
10113136110143
1143a87426081
1219b15079b67
13a890159094
1456938daba7
152e225c562d
hex1a57700a3f

113136110143 has 6 divisors (see below), whose sum is σ = 131607311856. Its totient is φ = 96973808652.

The previous prime is 113136110141. The next prime is 113136110183. The reversal of 113136110143 is 341011631311.

It is not a de Polignac number, because 113136110143 - 21 = 113136110141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113136110141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1154450055 + ... + 1154450152.

It is an arithmetic number, because the mean of its divisors is an integer number (21934551976).

Almost surely, 2113136110143 is an apocalyptic number.

113136110143 is a deficient number, since it is larger than the sum of its proper divisors (18471201713).

113136110143 is an equidigital number, since it uses as much as digits as its factorization.

113136110143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2308900221 (or 2308900214 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 113136110143 its reverse (341011631311), we get a palindrome (454147741454).

The spelling of 113136110143 in words is "one hundred thirteen billion, one hundred thirty-six million, one hundred ten thousand, one hundred forty-three".

Divisors: 1 7 49 2308900207 16162301449 113136110143