11314011121 has 16 divisors (see below), whose sum is σ = 13655061504. Its totient is φ = 9164312784.

The previous prime is 11314011113. The next prime is 11314011133. The reversal of 11314011121 is 12111041311.

It is a cyclic number.

It is not a de Polignac number, because 11314011121 - 2³ = 11314011113 is a prime.

It is a super-2 number, since 2×11314011121² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11314011095 and 11314011104.

It is not an unprimeable number, because it can be changed into a prime (11314011101) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 409971 + ... + 436696.

It is an arithmetic number, because the mean of its divisors is an integer number (853441344).

Almost surely, 2^11314011121 is an apocalyptic number.

It is an amenable number.

11314011121 is a deficient number, since it is larger than the sum of its proper divisors (2341050383).

11314011121 is an equidigital number, since it uses as much as digits as its factorization.

11314011121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 846780.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 11314011121 its reverse (12111041311), we get a palindrome (23425052432).

The spelling of 11314011121 in words is "eleven billion, three hundred fourteen million, eleven thousand, one hundred twenty-one".