11314011133 has 2 divisors, whose sum is σ = 11314011134. Its totient is φ = 11314011132.

The previous prime is 11314011113. The next prime is 11314011157. The reversal of 11314011133 is 33111041311.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6063269689 + 5250741444 = 77867^2 + 72462^2 .

It is a cyclic number.

It is not a de Polignac number, because 11314011133 - 2⁵ = 11314011101 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11314011133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11314011113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657005566 + 5657005567.

It is an arithmetic number, because the mean of its divisors is an integer number (5657005567).

Almost surely, 2^11314011133 is an apocalyptic number.

It is an amenable number.

11314011133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11314011133 is an equidigital number, since it uses as much as digits as its factorization.

11314011133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 11314011133 its reverse (33111041311), we get a palindrome (44425052444).

The spelling of 11314011133 in words is "eleven billion, three hundred fourteen million, eleven thousand, one hundred thirty-three".