Base | Representation |
---|---|
bin | 110100101011110101… |
… | …1010010001101000011 |
3 | 101211000221002022022121 |
4 | 1221113223102031003 |
5 | 3323202332123433 |
6 | 123550441145111 |
7 | 11113501050322 |
oct | 1512753221503 |
9 | 354027068277 |
10 | 113140114243 |
11 | 43a89710452 |
12 | 19b1648b197 |
13 | a890c2b780 |
14 | 56942600b9 |
15 | 2e22b16c2d |
hex | 1a57ad2343 |
113140114243 has 8 divisors (see below), whose sum is σ = 121849470288. Its totient is φ = 104431653984.
The previous prime is 113140114187. The next prime is 113140114253. The reversal of 113140114243 is 342411041311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113140114243 - 233 = 104550179651 is a prime.
It is not an unprimeable number, because it can be changed into a prime (113140114253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50880 + ... + 478402.
It is an arithmetic number, because the mean of its divisors is an integer number (15231183786).
Almost surely, 2113140114243 is an apocalyptic number.
113140114243 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
113140114243 is a deficient number, since it is larger than the sum of its proper divisors (8709356045).
113140114243 is a wasteful number, since it uses less digits than its factorization.
113140114243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 447893.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 113140114243 its reverse (342411041311), we get a palindrome (455551155554).
The spelling of 113140114243 in words is "one hundred thirteen billion, one hundred forty million, one hundred fourteen thousand, two hundred forty-three".
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