Base | Representation |
---|---|
bin | 110100101011110101… |
… | …1010010001101001101 |
3 | 101211000221002022022222 |
4 | 1221113223102031031 |
5 | 3323202332124003 |
6 | 123550441145125 |
7 | 11113501050335 |
oct | 1512753221515 |
9 | 354027068288 |
10 | 113140114253 |
11 | 43a89710461 |
12 | 19b1648b1a5 |
13 | a890c2b78a |
14 | 56942600c5 |
15 | 2e22b16c38 |
hex | 1a57ad234d |
113140114253 has 2 divisors, whose sum is σ = 113140114254. Its totient is φ = 113140114252.
The previous prime is 113140114187. The next prime is 113140114273. The reversal of 113140114253 is 352411041311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 108433879849 + 4706234404 = 329293^2 + 68602^2 .
It is a cyclic number.
It is not a de Polignac number, because 113140114253 - 28 = 113140113997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113140114273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56570057126 + 56570057127.
It is an arithmetic number, because the mean of its divisors is an integer number (56570057127).
Almost surely, 2113140114253 is an apocalyptic number.
It is an amenable number.
113140114253 is a deficient number, since it is larger than the sum of its proper divisors (1).
113140114253 is an equidigital number, since it uses as much as digits as its factorization.
113140114253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 113140114253 its reverse (352411041311), we get a palindrome (465551155564).
The spelling of 113140114253 in words is "one hundred thirteen billion, one hundred forty million, one hundred fourteen thousand, two hundred fifty-three".
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